A ∪ B = {x: x ϵ A or x ϵ B }
= {2, 3, 5, 7, 9 }
(A∪B)’ means Complement of (A∪B) with respect to universal set U.
So,
(A∪B)’ = U– (A∪B)’
U–( A∪B)’ is defined as {x ϵ U : x ∉ (A∪B)’}
U = {2, 3, 5, 7, 9}
(A∪B)’ = {2, 3, 5, 7, 9 }
U–( A∪B)’ = ϕ
Now
A’ means Complement of A with respect to universal set U.
So,
A’ = U–A
U–A is defined as {x ϵ U : x ∉ A}
U = {2, 3, 5, 7, 9}
A = {3, 7}
A’ = {2, 5, 9}
B’ means Complement of B with respect to universal set U.
So,
B’ = U–B
U–B is defined as {x ϵ U : x ∉ B}
U = {2, 3, 5, 7, 9}
B = {2, 5, 7, 9}.
B’ = {3}
A’ ∩ B’ = = {x:x ϵ A’ and x ϵ C’ }.
= ϕ.
Hence verified.