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If f(x) = cos (log x), then f(x)f(y)-\(\frac{1}{2}\){f(\(\frac{x}{y}\))+f(xy)} has the value

A. -1 

B. 1/2 

C. -2

D. None of these

1 Answer

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Best answer

Option : (D)

f(x) = cos (log x)

Now,

f(x)f(y)-\(\frac{1}{2}\){f(\(\frac{x}{y}\))+f(xy)}

= cos(log x) cos(log y)-cos(log x) cos(log y) 

= 0

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