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In a triangle ABC, a = 4, b = 3, ∠A = 60° then c is a roof of the equation A. c^2 – 3c – 7 = 0 B. c^2 + 3c + 7 = 0

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In a triangle ABC, a = 4, b = 3, ∠A = 60°  then c is a roof of the equation

A. c2 – 3c – 7 = 0

B. c2 + 3c + 7 = 0

C. c2 – 3c + 7 = 0

D. c2 + 3c – 7 = 0

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1 Answer

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Best answer

Correct option is C. c2 – 3c + 7 = 0

We know by cosine law,

3c = c2 -7

c2 - 3c - 7 = 0

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