Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.5k views
in Trigonometry by (28.4k points)
closed by

Prove that :  (sin 9A - sin 7A)/(cos 7A - cos 9A) = cot 8A

\(\frac{sin\,9A\,-\,sin\,7A}{cos\,7A\,-cos\,9A}\) = cot 8A

1 Answer

+1 vote
by (29.5k points)
selected by
 
Best answer

(sin 9A - sin 7A)/(cos 7A - cos 9A) = cot 8A

Take L.H.S.:

\(\frac{sin\,9A\,-\,sin\,7A}{cos\,7A\,-cos\,9A}\)

= R.H.S. 

Hence Proved

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...