Given,
⇒ 2sin2x + 2cos2x = \(2^{\frac{1}2}+2^{\frac{1}2}\)
On comparing both sides, we have
sin2 x = cos2 x = 1/2
Note: If we want to give solution using above two equations then task will become tedious as sin x can be positive at that time cos will be negative and similar 4-5 cases will arise. So inspite of combining all solutions at the end,we proceed as follows
combining both we can say that,
all the solutions of first 2 equations combined will satisy this single equation
tan2 x = 1
