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If cos x + √3 sin x = 2, then x = 

A\(\frac{π}3\)

B\(\frac{2π}3\)

C\(\frac{4π}3\)

D.\(\frac{5π}3\)

1 Answer

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Best answer

cos2x = (2 - √3 sin x)2 

1-sin2x = 4+3 sin2x - 4√3 sin x 

4 sin 2x - 4√3 sin x+3 = 0 

sin x = \(\frac{\sqrt3}2\) 

x = \(\frac{π}3\)

Option A

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