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The value of \(\frac{\text{cos 3x}}{\text{2 cos 2x - 1}}\) is equal to

A. cos x

B. sin x

C. tan x

D. None of these

1 Answer

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Best answer

Correct answer is A.

Given expression is \(\frac{\text{cos 3x}}{\text{2 cos 2x - 1}}\)

Consider

[using the formulae cos 3x = 4 cos3 x – 3 cos x and cos 2x = 2cos2x -1]

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