Given: Power = 2kW = 2000W
Current = 5A
Voltage = 220V
∴ Power = Current x Voltage
⇒ Current = \(\frac{Power}{Voltage}\) = \(\frac{2000}{220}\) = 9 A
Thus, the current exceeds the current rating of 5A. Therefore, either the fuse will burn out and if there is no fuse, then overloading will cause melting of wires which may result in short-circuiting or a fire.