
FOR LAMP 1: I1 = \(\frac{P_1}{V}\) = \(\frac{100}{220}\) = \(\frac{5}{11}\) A
FOR LAMP 2: I2 = \(\frac{P_2}{V}\) = \(\frac{60}{220}\) = \(\frac{3}{11}\) A
∴ Net current = I1+ I2
= \(\frac{3}{11}\) + \(\frac{5}{11}\)
= \(\frac{8} {11} \)
= 0.73 A
∴ Net current through the circuit is 0.73 A.