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Find the smallest positive integer value of n for which \(\frac{(1+i)^n}{(1-i)^{n-2}}\) is a real number.

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Let us write the given complex number as Z = \(\frac{(1+i)^n}{(1-i)^{n-2}}\)

Multiplying and dividing with (1-i)2 

We know that i2k is real for k≥0. 

∴ The least positive integral of n is 1.

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