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The HCF of two numbers is 23 and their LCM is 1449. If one of the numbers is 161, find the other.

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The HCF of two numbers is 23 and their LCM is 1449. If one of the numbers is 161, find the other.

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Let the two numbers be a and b. 

Let the value of a be 161. 

Given: HCF = 23 and LCM = 1449 

We know, a × b = HCF × LCM 

⇒ 161 × b = 23 × 1449

⇒ ∴ b = \(\frac{23\times1449}{161}\) = \(\frac{33327}{161}\) = 207

Hence, the other number b is 207.

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