We have,
eV0 = hv -φ0;
V0 = stopping potential
Or, V0 = \(\frac{h}{e}v\) - \(\frac{φ_0}{e}\)
∴V0 ∝ v
∴ v Vs V0 graph is a straight line as shown :

Comparing the above relation with y = mx + c,
We find the slope of graph is h/e.
The x- intercept is v0 and y- intercept is \(-\frac{ϕ_0}{e}\).
Thus,
v0 and V0 can be determined.