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By what least number should the given number be divided to get a perfect square number? In each case, find the number whose square is the new number.

(i) 4500

(ii) 7776

(iii) 8820

(iv) 4056

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(i) 4500

At first, We’ll resolve the given number into prime factors: 

Hence, 

4500 = 4 × 125 × 9 

= 2 × 2 × 3 × 3 × 5 × 5 × 5 

= (5 × 3 × 2) × (5 × 3 × 2) × 5 

In the above factors only 5 is unpaired 

So, in order to get a perfect square the given number should be divided by 5 

Hence, 

The number whose perfect square is the new number is as following: 

= (5 × 3 × 2) × (5 × 3 × 2) 

= (5 × 2 × 3) × (5 × 2 × 3) 

= (5 × 2 × 3)

= (30)2

(ii) 7776

At first, We’ll resolve the given number into prime factors: 

Hence, 

7776 = 32 × 243 

= 2 × 2 × 2 × 2 × 3 × 3 × 3 × 3 × 3 × 2 

= (2 × 2 × 3 × 3) × (2 × 2 × 3 × 3) × 2 × 3 

In the above factors only 2 and 3 are unpaired 

So, in order to get a perfect square the given number should be divided by 6 

Hence, 

The number whose perfect square is the new number is as following: 

= (2 × 2 × 3 × 3) × (2 × 2 × 3 × 3) 

= (2 × 2 × 3 × 3)

= (36)2

(iii) 8820

At first, We’ll resolve the given number into prime factors: 

Hence, 

8820 = 4 × 5 × 9 × 49 

= 2 × 2 × 3 × 3 × 7 × 7 × 5 

= (7 × 3 × 2) × (7 × 3 × 2) × 5 

In the above factors only 5 is unpaired 

So, in order to get a perfect square the given number should be divided by 5 

Hence, 

The number whose perfect square is the new number is as following: 

= (7 × 3 × 2) × (7 × 3 × 2) 

= (7 × 3 × 2)2 

= (42)2

(iv) 4056 

At first, We’ll resolve the given number into prime factors: 

Hence, 

4056 = 8 × 3 × 169 

= 2 × 2 × 13 × 13 × 3 × 2 

= (13 × 2) × (13 × 2) × 6 

In the above factors only 6 is unpaired 

So, in order to get a perfect square, the given number should be divided by 6 

Hence, 

The number whose perfect square is the new number is as following: 

= (13 × 2) × (13 × 2) 

= (13 × 2)2 

= (26)2

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