Question

Find the maximum number of students among whom 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and the same number of pencils.

Answer 1

Total number of pens = 1001. 

Total number of pencils = 910.

Maximum number of students who get the same number of pens and same number of pencils = 

HCF (1001, 910). 

Using prime factorization,

910 = 2 × 5 × 7 ×13. 

1001 = 7 × 11 × 13. 

Hence, 

HCF (1001, 910) = 7 × 13 = 91 

Hence, 

Maximum number of students who get the same number of pens (11) and same number of pencils (10) is 91.