Question

Find the zeroes of the quadratic polynomial f(x) = 6x² – 3.

Answer 1

To find the zeroes of the quadratic polynomial we will equate f(x) to 0 

∴f(x) = 0 

⇒ 6x² – 3 = 0 

⇒ 3(2x² – 1) = 0 

⇒ 2x² – 1 = 0 

⇒ 2x² = 1 

⇒ x² = \(\frac{1}2\)

⇒ x = ± \(\frac{1}{\sqrt2}\) 

Hence, 

the zeroes of the quadratic polynomial f(x) = 6x² – 3 are \(\frac{1}{\sqrt2}\), - \(\frac{1}{\sqrt2}\)