Given quadratic equation is :
3√3x2 + 10x + √3 = 0.
∴ a = 3√3, b = 10 and c = √3.
∴ Roots of given quadratic equation are x = \(\frac{-b±\sqrt{b^2-4ac}}{{2a}}\)
= \(\frac{-10±\sqrt{10^2-4\times 3\sqrt 3\times \sqrt 3}}{{2\times 3\sqrt 3}}\)

Hence,
The solution of given quadratic equation are x = \(\frac{-1}{3\sqrt 3}\)
And x = −√3.