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Show graphically that the system of equations 2x + 3y = 4, 4x + 6y = 12 is inconsistent.

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On a graph paper, draw a horizontal line X'OX and a vertical line YOY' as the x-axis and y-axis, respectively. 

Graph of 2x +3y = 4 

2x + 3y = 4 

⇒ 3y = (–2x + 4) …(i) 

Putting x = 2, we get y = 0 

Putting x = -1, we get y = 2 

Putting x = -4, we get y = 4 

Thus, we have the following table for the equation 2x + 3y = 4.

x 2 -1 -4
y 0 2 4

Now, plot the points A(2, 0), B(-1, 2) and C(-4, 4) on the graph paper. 

Join AB and BC to get the graph line AC. Extend it on both ways. 

Thus, the line AC is the graph of 2x + 3y = 4. 

Graph of 4x + 6y = 12 

4x + 6y = 12

⇒ 6y = (-4x + 12)

⇒ y = \(\frac{-4x+12}6\)...........(ii)

Putting x = 3, we get y = 0 

Putting x = 0, we get y = 2 

Putting x = 6, we get y = -2 

Thus, we have the following table for the equation 4x + 6y = 12.

x 3 0 6
y 0 2 -2

Now, on the same graph, plot the points A(3, 0), B(0, 2) and C(6, -2). 

Join PQ and PR to get the graph line QR. Extend it on both ways. 

Thus, QR is the graph of the equation 4x + 6y = 12.

It is clear from the graph that these two lines are parallel and do not intersect when produced. 

Hence, the given system of equations is inconsistent.

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