Given,
x/(x-5) > 1/2

For this inequation to be true,
There are two possible cases.
i. x + 5 > 0 and x – 5 > 0
⇒ x + 5 – 5 > 0 – 5 and
x – 5 + 5 > 0 + 5
⇒ x > –5 and x > 5
∴ x ∈ (–5, ∞) ∩ (5, ∞)
However,
(–5, ∞) ∩ (5, ∞) = (5, ∞)
Hence,
x ∈ (5, ∞)
ii. x + 5 < 0 and x – 5 < 0
⇒ x + 5 – 5 < 0 – 5 and
x – 5 + 5 < 0 + 5
⇒ x < –5 and x < 5
∴ x ∈ (–∞, –5) ∩ (–∞, 5)
However,
(–∞, –5) ∩ (–∞, 5) = (–∞, –5)
Hence,
x ∈ (–∞, –5)
Thus,
The solution of the given inequation is (–∞, –5)∪ (5, ∞).