Given,
1/(|x|-3) < 1/2
We know that,
If we take reciprocal of any inequality we need to change the inequality as well.
Also,
|x|–3≠0
⇒ |x|>3 or |x|<3
For |x|<3
⇒ –3<x<3
⇒ x∈ (–3, 3) ….(1)
∴ The equation can be re–written as–
|x| - 3 > 2
Adding 2 both the sides, we get–
|x|–3+3> 2+3
⇒ |x|>5
We know that,
|x |>a ⟺ x<-a or x>a
Here,
a = 5
⇒ x< -5 ….(2)
⇒ x ∈ (–∞,–5 ) or x ∈(5, ∞)
⇒ x ∈ (–∞,–5 ) ⋃ (–3, 3) ⋃ (5, ∞)
(from 1 and 2)
We can verify the answers using graph as well.
