Let the numbers be (2x + 1), (2x + 3) and (2x + 5)
According to the question
2x + 1 + 2x + 3 + 2x + 5 = 147
By cross multiplication
⇒ 6x + 9 = 147
⇒ 6x = 147 - 9
\(\Rightarrow \text{x}=\frac{138}{6}=23\)
So the numbers are (2x + 1) = 47, (2x + 3) = 49 and (2x + 5) = 51
