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in Linear Equations by (31.2k points)
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The width of a rectangle is two - thirds its length. If the perimeter is 180 metres, find the dimensions of the rectangle.

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Let the length and breadth of a rectangle be l m and b m 

According to the question

b = \(\frac{2}{3}l\) (A)

Perimeter of a rectangle = 2(l + b)

And 2(l + b) = 180

Putting (A) we get

\(2(l+\frac{2}{3}l)=180\)

\(\Rightarrow\frac{3l\,+\,2l}{3}=90\)

⇒ 5l = 90 × 3 

⇒ l = 54 m 

⇒ b = 2/3 (54) = 36m

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