Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.3k views
in Linear Equations by (30.8k points)
closed by

Subtract 4a2 + 5b2 - 6c2 + 8 from 2a2 - 3b2 - 4c2 - 5.

1 Answer

+1 vote
by (31.2k points)
selected by
 
Best answer

(2a2 - 3b2 - 4c2 – 5) – (4a2 + 5b2 - 6c2 + 8) 

= 2a2 - 3b2 - 4c2 – 5 - 4a2 - 5b2 + 6c2 – 8 

= - 2a2 - 8b2 + 2c2 - 13

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...