Question

What will be the percentage of iron (III) present in Fe_0.93O?

(a) 84.95%

(b) 45.64%

(c) 15.05%

(d) 44.36%

Answer 1

Answer is : (c) 15.05 %

According to valency concept, 3Fe²⁺ will be replaced by 2Fe³⁺.

Total loss of iron from one mole of FeO = 1 - 0.93 = 0.07

Total Fe³⁺ present in one molecule of FeO is 2 x 0.07 = 0.14

Total number of Fe (II) and Fe (III) present in one molecule of FeO = 0.93

Percentage of Fe (III) = \(\frac{0.14}{0.93}\) x 100 = 15.05%