The given equations are as follows:
6x + 3y = 7xy ………….(i)
3x + 9y = 11xy …………(ii)
For equation (i), we have:
For equation (ii), we have:
On substituting 3/y = v and 1/x = u in (iii) and (iv), we get:
6v + 3u = 7 ………..(v)
3v + 9u = 11 ……….(vi)
On multiplying (v) by 3, we get:
18v + 9u = 21 ………(vii)
On substituting y = 3/2 in (iii), we get:
⇒ x = 1
Hence, the required solution is x = 1 and y = 3/2
