What will be the output if she inputs 1, 4 and 5? How can you correct it?

Question

The following C++ code segment is a part of a program written by Smitha to find the average of 3 numbers. int a, b, c; float avg; 

cin>>a>>b>>c; 

avg=(a+b+c)/3; ‘ 

cout<<avg;,What will be the output if she inputs 1, 4 and 5? How can you correct it?

Answer 1

=(1 +4+5)/3 =10/3 =3.3333 Instead of this 3.3333 the output will be 3. This is because if both operands are integers an integer division will be occurred, that is the fractional part will be truncated. 

To get the correct out put do as follows 

case 1: int a,b,c; is replaced by float a,b,c; 

OR 

case 2: Replace (a+b+c)/3 by (a+b+c)/3.0; 

OR 

case 3: Type casting. Replace avg=(a+b+c)/3; by avg=(float)(a+b+c)/3;