We have
AM : MB = 1 : 2
⇒ MB/AM = 2/1
Adding 1 to both sides, we get

Now, In ∆AMN and ∆ABC
∠AMN = ∠ABC (corresponding angles in MN || BC)
∠ANM = ∠ACB (corresponding angles in MN || BC)
By AA similarity criterion, ∆AMN ~ ∆ ABC
If two triangles are similar, then the ratio of their areas is equal to the ratio of the squares of their corresponding sides.
