(i) Two rectangles are similar if their corresponding sides are proportional.
(ii) True Two circles of any radii are similar to each other.
(iii) false If two triangles are similar, their corresponding angles are equal and their corresponding sides are proportional.
(iv) True Suppose ABC is a triangle and M, N are

Construction: DE is expanded to F such that EF = DE
To proof = DE = 1/2 BC
Proof: In ∆ADE and ∆CEF
AE = EC (E is the mid point of AC)
DE = EF (By construction)
AED = CEF (Vertically Opposite angle)
By SAS criterion, ∆ADE ~ ∆CEF
CF = AD (CPCT)
⇒ BD = CF
∠ADE = ∠EFC (CPCT)
Since, ∠ADE and ∠EFC are alternative angles
Hence, AD ‖ CF and BD ‖ CF
When two sides of a quadrilateral are parallel, then it is a parallelogram
∴ DF = BC and BD ‖ CF
∴BDFC is a parallelogram
Hence, DF = BC
⇒ DE + EF = BC
⇒ DE = 1/2 BC
(v) False In ∆ABC, AB = 6 cm, ∠A = 45° and AC = 8 cm and in ∆DEF,DF = 9 cm, ∠D = 45° and DE = 12 cm, then ∆ABC ~ ∆DEF.
In ∆ABC and ∆DEF