1. Let A(0, 7, -10), B(1, 6, -6) and C(4, 9, -6) be the two points.

Now AB = BC, thus ABC is an isosceles triangle.
2. Let A(0, 7, 10), B(-1, 6, 6) and C(-4, 9, 6) be the two points.

Now AC2 = AB2 + BC2, thus ABC is a right triangle.
3. Let A(-1, 2, 1), B(1, -2, 5), C(4, -7, 8) and D(2, -3, 4) be the two points.

Now AB = CD, BC = AD, AC ≠ BD, thus A, B, C, D are vertices of a parallelogram.