Question

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of `15 m, 10 m and 7 m` respectively. From each From each can of paint `100m^2` of area is painted. How many cans of paint will she need to paint the room?

Answer 1

The surface area of the cuboidal hall needs to be painted `A = 2(lh+bh)+lb`
`A =2(10**7+7**15)+(15**10)`
`A = 2**175+150 = 500m^2`
Area painted by one can of paint `= 100m^2`
So, to paint complete room number of can of paint required `= 500/100 = 5`