Thirty men can do a piece of work in 16 days working 8 hours a day. How many men are needed to complete another work, which is twice the first one, in 10 days working 12 working a day?
The following are the steps involved in solving the above problem. Arrange them in sequential order.
`M_(2)=(30xx16xx8xx2x)/(x xx12xx10)`
`(30xx16xx8)/(x)=(M_(2)xx12xx10)/(2x)`
`(M_(1)D_(1)H_(1))/(W_(1))=(M_(2)D_(2)H_(2))/(W_(2))`
`M_(2)=64`
A. CBAD
B. ACBD
C. ABCD
D. BACD
