To Find: Describe the given events.
Explanation: when two dice are thrown then the no. of possible outcomes are 62 = 36
Now, According to the question,
A = Getting an even number of the first die.
A = {(2, 1)(2, 2)(2, 3)(2, 4)(2, 5)(2, 6)(4, 1)(4, 2)(4, 3)(4, 4)(6, 1)(6, 2)(6, 3)(6, 4)(6, 5)(6, 6)}
B = Getting an odd number on the first dice
B = {(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6) (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6) (5, 1) (5, 2) (5, 3) (5, 4) (5, 5)(5, 6)}
C = Getting at most 5 as the sum of numbers on the two dices.
C = {(1, 1)(1, 2)(1, 3)(1, 4)(2, 1)(2, 2)(2, 3)(3, 1)(3, 2)(4, 1)}
D = Getting a sum greater than 5 but less than 10
D = {(1, 5)(1, 6) (2, 4)(2, 5) (2, 6)(3, 3)(3, 4)(3, 5)(3, 6)(4, 2)(4, 3)(4, 4)(4, 5)(5, 1) (5, 2)(5, 3) (5, 4)(6, 1) (6, 2) (6, 3)}
E = Getting at least 10 as the sum of numbers on the dices
{(4, 6)(5, 5)(5, 6)(6, 4)(6, 5)(6, 6)}
F = Getting an odd number on one of the dices
{(1, 2)(1, 4)(1, 6)(2, 1)(2, 3)(2, 5)(3, 2)(3, 4)(3, 6)(4, 1)(4, 3)(4, 5)(5, 2)(5, 4)(5, 6)(6, 1)(6, 3)(6, 5) Now,
(i) A and B = AՌB = Փ
Since, There is no common events in Both A and B so the intersection is Null (Փ).
⇒ B or C = BUC
BUC = {(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6) (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6) (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)(2, 1)(2, 2)(2, 3)(4, 1)}
⇒ B and C = BՌC
BՌC = {(1, 1), (1, 2)(1, 3)(1, 4)(3, 1)(3, 2)}
⇒ A and E = AՌE
AՌE = {(4, 6)(6, 4)(6, 5)(5, 6)(6, 6)}
⇒ A or F = AUF
AUF = {(2, 1)(2, 2)(2, 3)(2, 4)(2, 5)(2, 6)(4, 1)(4, 2)(4, 3)(4, 4)(6, 1)(6, 2)(6, 3)(6, 4)(6, 5)(6, 6)(1, 2)(1, 4)(1, 6) (3, 2)(3, 4)(3, 6)(4, 5)(5, 2)(5, 4)(5, 6)}
(ii)
(a) True, because AՌB = Փ
(b) True, because AՌB = Փ and AUB = S
(c) False, because AՌC = Փ
(d) False, because CՌD = Փ but CUD≠S
(e) True, because CՌDՌE = Փ and CUDUE = S
(f) True, because A’ՌB’ = Փ
(g) False, because AՌBՌF = Փ and AUBUF = S