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If nC4 = nC6, find the value of 12Cn.

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We know that,

If nCp = nCq,

Then one of the following conditions need to be satisfied :

i. p = q 

ii. n = p + q

From the problem,

nC4 = nC6

We can say that,

⇒ 4 ≠ 6 

So, 

The condition(ii) must be satisfied, 

⇒ n = 4 + 6 

⇒ n = 10.

We need to find the value of 12Cn = 12C10

We know that,

nCr\(\frac{n!}{r!(n-r)!}\) ..... (1)

And also,

n! = n(n – 1)(n – 2)…………2.1

From (1)

∴ The value of 12C10 is 66.

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