We know that,
If nCp = nCq,
Then one of the following conditions need to be satisfied :
i. p = q
ii. n = p + q
From the problem,
nC4 = nC6
We can say that,
⇒ 4 ≠ 6
So,
The condition(ii) must be satisfied,
⇒ n = 4 + 6
⇒ n = 10.
We need to find the value of 12Cn = 12C10
We know that,
nCr = \(\frac{n!}{r!(n-r)!}\) ..... (1)
And also,
n! = n(n – 1)(n – 2)…………2.1
From (1)

∴ The value of 12C10 is 66.