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In the above figure, O is the centre of the circle and `AB=CD`. If `/_ APB=110^(@)`, then find the angle made by the chord CD at the centre.

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In the above figure, O is the centre of the circle and `AB=CD`. If `/_ APB=110^(@)`, then find the angle made by the chord CD at the centre.
A. `220^(@)`
B. `110^(@)`
C. `120^(@)`
D. `140^(@)`
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Correct Answer - d
(i) Equal chords subtend equal angles at the centre.
(ii) JoinAO, OC, OB and OD.
(iii) Reflex `/_ AOB =2 /_APB,` use this to find `/_AOB` as `/_ AOB =360^(@) - 2 /_ APB`
(iv)` /_AOB = /_ COD`
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