Let us first calculate the frequency of the sound waves
`V = n lamda` (1)
Substituting the values of `V = 332 ms^(-2) and lamda = 2m, " w get " (V)/(lamda) = (332)/(2)`
`n = 166 Hz`
The frequency of the sound waves remains constant, as it travels from air to water. Hence, using the formula
`V = n lamda` and substituting `n = 166 Hz` and
`lamda = 850 cm = 8.5 m`, we get
`V = 166 xx 8.5 = 1411 ms^(-2)`