Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
168 views
in Physics by (88.8k points)
closed by
In a vernier callipers 15 vernier scale divisions correspond to 14 main scale divisions and one main scale division is equal to 1.5 mm. An object is held scale division is equal to 1.5 mm. An object is held between the external jaw of the given vernier caliipers. If the zeroth division of the vernier scale is to the left of the 20^(th) divison of the main scale, find teh measurement of the object, if teh 14th division of the vernier scale coincides with the main scale division.

1 Answer

0 votes
by (97.2k points)
selected by
 
Best answer
Given, 1 M.S.D. = M.S.D.= 1.5mm
Number of V.S.D,s = 15 rArr N = 15
L.C. of the vernier callipers,
L.C. = `(1M.S.D.)/(N)= (1.5mm)/(15)`
rArr L.C.= 0.1 mm
Given M.S.R =19 `xx` 1.5 mm = 28.5 mm
Given vernier coincidence, V.C. = 14
=Measurement of length of givne object = M.S.R.+ V.C.`xx` L.C. = 28.5 mm + 14 `xx`0.1 mm
28.5 mm + 1.4 mm
29.9 mm = 2.99 cm

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...