Given, 1 M.S.D. = M.S.D.= 1.5mm
Number of V.S.D,s = 15 rArr N = 15
L.C. of the vernier callipers,
L.C. = `(1M.S.D.)/(N)= (1.5mm)/(15)`
rArr L.C.= 0.1 mm
Given M.S.R =19 `xx` 1.5 mm = 28.5 mm
Given vernier coincidence, V.C. = 14
=Measurement of length of givne object = M.S.R.+ V.C.`xx` L.C. = 28.5 mm + 14 `xx`0.1 mm
28.5 mm + 1.4 mm
29.9 mm = 2.99 cm