Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
378 views
in Statistics by (88.8k points)
closed by
The marks obtained (out of 100) by a class of 80 students are given below:
image
Construct a histogram to represent the data above

1 Answer

0 votes
by (97.2k points)
selected by
 
Best answer
Here, the class intervals are of unequal width. So, we shall first input compute adjusted frequencies of each class. The minimum class-size is 20-10=10. The adjusted frequencies are computed by using the following formula
`"Adjusted frequency" = ("minimum class-size")/("class-size") xx "frequency of the class"`
image
Now, we construct rectangles with class-limits as bases and respective adjusted frequencies as heights.
image

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...