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The point (0,3) lies on the graph of the linear equation 3x+4y=12.

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The point (0,3) lies on the graph of the linear equation 3x+4y=12.
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If we put x=0 and y=3 in LHS of the given equation, we find
LHS`=3xx0+4xx3=0+12=12`=RHS
Hence, (0,3) lies on the linear equation 3x+4y=12.
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