The sum and sum of squares corresponding to length x (in cm) and weight y (in gm) of 50 plant products are given below: Σ_{i=1}^50 x_i = 212,

Question

The sum and sum of squares corresponding to length x (in cm) and weight y (in gm) of 50 plant products are given below:

\(\displaystyle\sum_{i-1}^{50} x_i = 212, \displaystyle\sum_{i=1}^{50} x_i^2 = 902.8\)

\(\displaystyle\sum_{i-1}^{50} y_i = 216, \displaystyle\sum_{i=1}^{50} y_i^2 = 1457.6\)

which is more varying, the length or weight?

Answer 1

Here,

\(\displaystyle\sum_{i-1}^{50} x_i = 212, \displaystyle\sum_{i=1}^{50} x_i^2 = 902.8\)

\(\displaystyle\sum_{i-1}^{50} y_i = 216, \displaystyle\sum_{i=1}^{50} y_i^2 = 1457.6\)

Now

\(\bar x = \frac{212}{50} = 4.24\),

C.V of weight = \(\frac{1.38}{5.22} \times 100 = 26.44\)

C.V  of weight > C.V of length

Thus weight have more variability than length