CE is angle bisector of `/_ ACQ`
DF is angle bisector of `/_CDS`
`CF || DF`
AD is transversal line for CE & DF
`/_ ACE = /_ CDF`
`/_ ACQ = 2 xx /_ACE`
`/_AC= 1/2 /_ ACQ`
So, `1/2 /_ACQ = /_CDS`
`/_CDF = 1/2/_CDS`
So, `PQ ||RS`
AB acts as the transversal line
Answer