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Two lines AB and CD intersect at a point O such that `angleBOC+angleAOD`=`280^(@)`, as shown in the figure. Find all the four angles.

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Correct Answer - `angleBOC=140^(@), angleAOD=140^(@), angleAOC=40^(@), angleBOD=40^(@)`
`angleBOC=angleAOD` [vertically opposite `angles`]
`:. angleBOC=angleAOD=140^(@)`.
`angleAOC+angleAOD=180^(@) implies angleAOC+140^(@)=180^(@) implies angleAOC=40^(@)`.
`angleBOD=angleAOC=40^(@)`.

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