Correct Answer - `angleBOC=140^(@), angleAOD=140^(@), angleAOC=40^(@), angleBOD=40^(@)`
`angleBOC=angleAOD` [vertically opposite `angles`]
`:. angleBOC=angleAOD=140^(@)`.
`angleAOC+angleAOD=180^(@) implies angleAOC+140^(@)=180^(@) implies angleAOC=40^(@)`.
`angleBOD=angleAOC=40^(@)`.