Show that each diagonal of a parallelogram divide it into two congruent triangles.
The following are the steps involved in showing the above result. Arrange them in sequential order.
A) In `triangleABC` and `triangleCDA`, AB=DC and BC=AD `(therefore` opposite angles of parallelogram) AC=AC (common side).
B) Let ABCD be a parallelogram. Join AC.
C) By SSS congruence property, `triangleABC ~=triangleCDA`.
D) Similarly, BD divides the triangle into two congruent triangles.
A. BACD
B. BDAC
C. BADC
D. BDCA