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In the given figure, P,Q,R and S are concylic points, and O is the mid-point of the diameter QS. If `angleQPR=25^(@)`, then find `angleSQR`.
image
A. `130^(@)`
B. `120^(@)`
C. `75^(@)`
D. `100^(@)`

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Correct Answer - A
Given, `angleQPR=25^(@)`.
Since, QS is the diameter, `angleQPS=90^(@)`.
`rArr angleSPR = 90-25^(@)=65^(@)`
`therefore angleSOR=2 xx 65^(@)=130^(@)`.

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