Question

In the adjoining figure `O` is the centre of the circle . If chord `AB=2` cm radius `OA=2` cm, then find the value of `angle ACB`.

Answer 1

Here, `OA =OB =2 cm`
and `AB=2cm`
`thereforeDeltaOAB` is an equilateral triangle.
`rArrtriangle AOB =60^(@)`
Now, angles subtended by arc AB at
centre `=angleAOB`
remaining circle `=angle ACB`
`therefore angle ACB=(1)/(2)angle AOB`
`=(1)/(2)xx60^(@)`
`=30^@`