STEPS OF CONSTRUCTION
(i) Draw `AB=3.6` cm.
(ii) With A as centre and 3 cm as radius, draw an arc.
(iii) With B as centre and 4.8 cm as radius, draw another arc, cutting the previous arc at A.
(iv) Join AC and BC.
Then, `Delta ABC` is the required triangle.
(v) Clearly, the angle opposite to the smallest side is smallest.
So, `angleB` is the smallest angle.
(vi) So, we draw BD, the bisector of `angleB`.
On measuring, we find that `angleABD=angleCBD=20^(@)`.
