Given :
AB = 3.5 cm , BC = 3.58 cm , CD = DA = 4.5 cm , BD = 5.6 cm.
Construction :
Step 1 : Draw segment AB of length 3.5 cm.
Step 2 : Taking A as centre draw an arc of radius 4.5 cm.
Step 3 : Taking B as centre draw an arc of radius 5.6 cm, which cuts the arc drawn in step 2. Point of intersection of two arcs is D.
Step 4 : Join AD and BD.
Step 5 : Taking B as centre draw an arc of radius 3.58 cm.
Step 6 : Taking D as centre draw arc of radius 4.5 cm, which cuts the arc drawn in step 5. Point of intersection of two arcs is C.
Step 7 : Join BC and CD.
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ABCD is the required quadrilateral