Question

Construct a quadrilateral PQRS in which PQ=5cm, QR=6.5cm, ∠P = ∠R = 100° and ∠S = 75° .

Answer 1

Given :

PQ = 5 cm , QR = 6.5 cm , \(\angle P=100^\circ,\angle R=100^\circ,\angle S=75^\circ\)

Answer :

Sum of all angles of a quadrilateral is 360

Construction :

Step 1 : Draw segment PQ of length 5 cm.

Step 2 : Draw angle PQC of 85 degrees.

Step 3 : Taking Q as centre draw arc of radius 6.5 cm which cuts the segment QC. Point of intersection is R

Step 4 : Draw angle QRF of 100 degrees.

Step 5 : Draw angle QPG of 100 degrees.

Step 6 : Point of intersection of segments PG and RF is S

PQRS is the required quadrilateral.