Given, Numbers of observations are given.
To Find: Calculate the Mean Deviation.
Formula Used: Mean Deviation = \(\frac{\Sigma d_i}{n}\)
Explanation: Here, Observations 36, 72, 46, 42, 60, 45, 53, 46, 51, 49 are Given. Deviation |d| = |x-Mean|
Mean = Σ\(\frac{|x_i|}{n}\)
Mean of the Given Observations = \(\frac{36+72+46+42+60+42+60+45+53+46+51+49}{10}\) = \(\frac{500}{10}\)
And, The number of observations is 10
Now, The Mean Deviation is
| Xi |
|di| = |xi-50| |
| 38 |
12 |
| 70 |
20 |
| 48 |
2 |
| 40 |
10 |
| 42 |
8 |
| 55 |
5 |
| 63 |
13 |
| 46 |
4 |
| 54 |
4 |
| 44 |
6 |
| Total Σxi = 500 |
84 |
Mean Deviation = \(\frac{\Sigma d_i}{n}\)
Mean Deviation of the given Observations = \(\frac{84}{10}\) = 8.4
Hence, The Mean Deviation is 8.4
