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How many moles are `9.033 xx 10^(24)` atoms of helium (He) ?

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We know that :
`6.022 xx 10^(23)` atoms of helium `=1` mole
So, `9.033 xx 10^(24)` atoms of helium `= (1)/(6.022 xx 10^(23)) xx 9.033 xx 10^(24)`
`= 15` moles , (or `15` mole)
Thus, `9.033 xx 10^(24)` atoms of helium are `15` moles of atoms.

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