We know that,
1 m = 100 cm
Also,
Volume of a cuboid = Length × Breadth × Height
Therefore,
Volume of the original block = 225 × 150 × 27
= 911250 cm3
Given that,
Length of the edge of the cube = 45 cm
Therefore,
Volume of one cube = a3 = (45)3
= 91125 cm3
Hence,
Total number of blocks that can be cast = \(\frac{Volume\,of\,the\,block}{Volume\,of\,the\,cube}\)
= \(\frac{911250}{91125}\)
= 10