Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
173 views
in Chemistry by (43.5k points)
closed by
In an organic chemistery laboratory a scientist subjecteda hydrocarbon to combustion The products occupied a volume ratio of 4:3 under the same conditions of temperature and pressure .The scientist drew the possible structures of the hydrocarbon. She then subjected the compound to ozonolysis to identify the exact structure. Predict the products formed when the compound is treated with bro-mine water.

1 Answer

0 votes
by (40.8k points)
selected by
 
Best answer
General combustion equation is
`C_xH_y+(x+y/4)O_2rarrxx.CO_2+y/2H_2C` As the molar ratio of `CO_2` and `H_2O` is 4:3
x=4 and `y/2=3rArry=6`
`thereforeX=C_4H_6`
image
Since it reacts With bromine water and its formula indicates that X is butyne
`therefore` X may be 1-Butyne or 2- Butyne
image

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...